MathematicsChapter 4: Linear and Quadratic Inequalities
Quadratic Inequalities
For (x-p)(x-q)>0 the product is positive outside the roots (same sign).
Learning objectives
- Explain quadratic inequalities using the correct definitions, conditions, and notation.
- Apply outside vs between, test a point correctly in routine and exam-style questions.
- Show each important step, simplify the result, and check that it satisfies the original conditions.
Definition
For (x-p)(x-q)>0 the product is positive outside the roots (same sign). For <0 it is negative between the roots (opposite signs). If the parabola opens up (a>0), >0 is outside and <0 is inside. Sketch a sign chart: test a point in each interval.
Mathematical form
test x = -2: (-)(-) > 0 true
test x = 0: (+)(-) < 0 false
test x = 4: (+)(+) > 0 true
x = -1 and x
Where / symbols
- QUADRATIC INEQUALITIES
- For (x-p)(x-q)>0 the product is positive outside the roots (same sign). For <0 it is negative between the roots (opposite signs). If the parabola opens up (a>0), >0 is outside and <0 is inside. Sketch a sign chart: test a point in each interval.
- PRODUCT FORM
- (x+1)(x-3)>0 when x<-1 or x>3. (x-9)(x+1)<0 when -1<x<9. Equal roots and = change whether endpoints are included.
- FROM STANDARD FORM
- x^2 - x - 90 > 0 factors as (x-10)(x+9)>0, so x<-9 or x>10. x^2+4x-21<0 is (x+7)(x-3)<0 so -7<x<3.
Overview
Roots first, then signs:
Product Form
(x+1)(x-3)>0 when x<-1 or x>3. (x-9)(x+1)<0 when -1<x<9. Equal roots and = change whether endpoints are included.
Examples x<-1 or x>3 · -1<x<9 · Include roots only for <= or >=
From Standard Form
x^2 - x - 90 > 0 factors as (x-10)(x+9)>0, so x<-9 or x>10. x^2+4x-21<0 is (x+7)(x-3)<0 so -7<x<3.
Examples (x-10)(x+9)>0 · x^2+4x-21<0 · a>0 opens up
WHAT — QUADRATIC INEQUALITIES
For (x-p)(x-q)>0 the product is positive outside the roots (same sign). For <0 it is negative between the roots (opposite signs). If the parabola opens up (a>0), >0 is outside and <0 is inside. Sketch a sign chart: test a point in each interval. The symbols and conditions are part of the mathematics, so include them when stating the rule.
WHY — Why this topic matters
Quadratic Inequalities matters because inequalities describe ranges and limits rather than one exact value. They are used for constraints, graphs, optimisation, and real situations such as budgets, dimensions, and capacity.
HOW — How to solve and explain it
Start by identifying what is given and what must be found. Work through PRODUCT FORM, then FROM STANDARD FORM. Worked: solve (x + 1)(x - 3) > 0. roots: x = -1 and x = 3 intervals: x < -1, -1 < x < 3, x > 3 test x = -2: (-)(-) > 0 true test x = 0: (+)(-) < 0 false test x = 4: (+)(+) > 0 true solution: x < -1 or x > 3 Finish by checking signs, restrictions, units, and whether the answer matches the question.
Worked example
- solve (x + 1)(x - 3) > 0.
- roots: x = -1 and x = 3
- intervals: x < -1, -1 < x < 3, x > 3
- test x = -2: (-)(-) > 0 true
- test x = 0: (+)(-) < 0 false
- test x = 4: (+)(+) > 0 true
- solution: x < -1 or x > 3
In simple words
Do not solve (x+1)(x-3)>0 as if it were =0 and then 'the roots are the answer'. The roots are the boundaries, not the solution of a strict inequality.
Key points
- outside vs between
- test a point
- >0 outside if a>0
- factor then chart
Exam preparation
Exam Focus
Quick revision
Revision Zone
Review the key facts, formulas and checks before you move on.Quadratic Inequalities
Sticky Notes · Quick Revision
Core Idea
- For (x-p)(x-q)>0 the product is positive outside the roots (same sign). For <0 it is negative between the roots (opposite signs). If the parabola opens up (a>0), >0 is outside and <0 is inside. Sketch a sign chart: test a point in each interval.
PRODUCT FORM
- (x+1)(x-3)>0 when x<-1 or x>3. (x-9)(x+1)<0 when -1<x<9. Equal roots and = change whether endpoints are included.
FROM STANDARD FORM
- x^2 - x - 90 > 0 factors as (x-10)(x+9)>0, so x<-9 or x>10. x^2+4x-21<0 is (x+7)(x-3)<0 so -7<x<3.
Worked Method
- Worked: solve (x + 1)(x - 3) > 0.
- roots: x = -1 and x = 3
- intervals: x < -1, -1 < x < 3, x > 3
- test x = -2: (-)(-) > 0 true
- test x = 0: (+)(-) < 0 false
- test x = 4: (+)(+) > 0 true
- solution: x < -1 or x > 3
Common Misconception
- Do not solve (x+1)(x-3)>0 as if it were =0 and then 'the roots are the answer'. The roots are the boundaries, not the solution of a strict inequality.
FBISE Exam Check
- Do not solve (x+1)(x-3)>0 as if it were =0 and then 'the roots are the answer'. The roots are the boundaries, not the solution of a strict inequality.
60-second revision
- For (x-p)(x-q)>0 the product is positive outside the roots (same sign).
- PRODUCT FORM: (x+1)(x-3)>0 when x<-1 or x>3.
- FROM STANDARD FORM: x^2 - x - 90 > 0 factors as (x-10)(x+9)>0, so x<-9 or x>10.
- Worked-method reminder: solution: x < -1 or x > 3
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