MathematicsChapter 3: Vectors
Cross Product in Components
a x b = det of a 3x3 with row 1 = i j k, row 2 = components of a, row 3 = components of b (school mnemonic).
Learning objectives
- State the main ideas and notation used in cross product in components.
- Apply the rules of cross product in components in a clear, step-by-step solution.
- Check signs, conditions, and the final answer for mathematical accuracy.
Definition
a x b = det of a 3x3 with row 1 = i j k, row 2 = components of a, row 3 = components of b (school mnemonic). Expand: (a2 b3 - a3 b2) i - (a1 b3 - a3 b1) j + (a1 b2 - a2 b1) k. Distributive: a x (b+c) = a x b + a x c. Angle: sin theta = |a x b| / (|a||b|). Meaning: the determinant is just a compact way to write those three 2x2 minors.
Mathematical form
b = det of a 3x3 with row 1
theta =
Where / symbols
- CROSS PRODUCT IN COMPONENTS
- a x b = det of a 3x3 with row 1 = i j k, row 2 = components of a, row 3 = components of b (school mnemonic). Expand: (a2 b3 - a3 b2) i - (a1 b3 - a3 b1) j + (a1 b2 - a2 b1) k. Distributive: a x (b+c) = a x b + a x c. Angle: sin theta = |a x b| / (|a||b|). Meaning: the determinant is just a compact way to write those three 2x2 minors.
- 1. THE DETERMINANT
- Write i j k on top. Compute the three cofactors. Watch the minus in front of j. Practice one fully written expansion.
- 2. USES
- Area. Torque tau = r x F named (physics). Perp vector to a plane of two vectors. If the result is 0, the vectors are parallel (or one is 0).
Overview
Expand, then the angle:
The Determinant
Write i j k on top. Compute the three cofactors. Watch the minus in front of j. Practice one fully written expansion.
Examples i (a2b3-a3b2) · - j (a1b3-a3b1) · k (a1b2-a2b1)
Uses
Area. Torque tau = r x F named (physics). Perp vector to a plane of two vectors. If the result is 0, the vectors are parallel (or one is 0).
Examples sin theta from |cross| · Check a · (a x b) = 0 · Distributive
WHAT — CROSS PRODUCT IN COMPONENTS
a x b = det of a 3x3 with row 1 = i j k, row 2 = components of a, row 3 = components of b (school mnemonic). Expand: (a2 b3 - a3 b2) i - (a1 b3 - a3 b1) j + (a1 b2 - a2 b1) k. Distributive: a x (b+c) = a x b + a x c. Angle: sin theta = |a x b| / (|a||b|). Meaning: the determinant is just a compact way to write those three 2x2 minors.
RULE — 1. THE DETERMINANT
Write i j k on top. Compute the three cofactors. Watch the minus in front of j. Practice one fully written expansion.
METHOD — 2. USES
Area. Torque tau = r x F named (physics). Perp vector to a plane of two vectors. If the result is 0, the vectors are parallel (or one is 0).
WORKED EXAMPLE
Worked: <1,2,3> x <4,5,6>. i (12-15) - j (6-12) + k (5-8) i (-3) - j (-6) + k (-3) = -3 i + 6 j - 3 k
How to answer a cross product in components question
- Identify the given quantities, notation, and required result.
- Choose the matching rule and write it before substitution.
- Work one algebraic step at a time, keeping brackets and signs clear.
- Check restrictions, simplify the result, and verify it where possible.
Worked example
- <1,2,3> x <4,5,6>.
- i (12-15) - j (6-12) + k (5-8)
- i (-3) - j (-6) + k (-3)
- = -3 i + 6 j - 3 k
In simple words
The j-component formula already includes the minus from the cofactor. Do not minus twice.
Key points
- ijk determinant mnemonic
- middle component has a minus
- minus on j
- area and normal
Exam preparation
Exam Focus
Quick revision
Revision Zone
Review the key facts, formulas and checks before you move on.Cross Product in Components
Sticky Notes · Quick Revision
Core Idea
- a x b = det of a 3x3 with row 1 = i j k, row 2 = components of a, row 3 = components of b (school mnemonic).
- Expand: (a2 b3 - a3 b2) i - (a1 b3 - a3 b1) j + (a1 b2 - a2 b1) k.
- Distributive: a x (b+c) = a x b + a x c.
1. THE DETERMINANT
- Write i j k on top.
- Compute the three cofactors.
- Watch the minus in front of j.
- Practice one fully written expansion.
2. USES
- Area.
- Torque tau = r x F named (physics).
- Perp vector to a plane of two vectors.
- If the result is 0, the vectors are parallel (or one is 0).
Worked Example
- Worked: <1,2,3> x <4,5,6>.
- i (12-15) - j (6-12) + k (5-8)
- i (-3) - j (-6) + k (-3)
- = -3 i + 6 j - 3 k
Common Misconception
- The j-component formula already includes the minus from the cofactor. Do not minus twice.
FBISE Exam Check
- State the rule for cross product in components before substituting values.
- Show the main algebra steps, keep exact values where possible, and check every condition.
60-second revision
- a x b = det of a 3x3 with row 1 = i j k, row 2 = components of a, row 3 = components of b (school mnemonic).
- Expand: (a2 b3 - a3 b2) i - (a1 b3 - a3 b1) j + (a1 b2 - a2 b1) k.
- Distributive: a x (b+c) = a x b + a x c.
- The j-component formula already includes the minus from the cofactor. Do not minus twice.
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