MathematicsChapter 8: Fundamentals of Trigonometry
Tan(a±b) and Double Angle
tan(A+B)=(tan A + tan B)/(1 - tan A tan B), provided the cosine in the bottom is not zero (defined).
Learning objectives
- State the main ideas and notation used in tan(a±b) and double angle.
- Apply the rules of tan(a±b) and double angle in a clear, step-by-step solution.
- Check signs, conditions, and the final answer for mathematical accuracy.
Definition
tan(A+B)=tan A + tan B1 - tan A tan B, provided the cosine in the bottom is not zero (defined). tan(A-B)=tan A - tan B1 + tan A tan B. Double: sin 2A = 2 sin A cos A, cos 2A = cos2 A - sin2 A = 2 cos2 A - 1 = 1 - 2 sin2 A, tan 2A = 2 tan A1-tan2 A. Meaning: divide sin compound by cos compound and divide through by cos A cos B.
Mathematical form
tan45=1, tan30=1/sqrt(3)
tan75 = 1 + 1/sqrt(3)1 - 1/sqrt(3)
A = 2 cos2 A - 1
tan45=1
Where / symbols
- TAN(A±B) AND DOUBLE ANGLE
- tan(A+B)=(tan A + tan B)/(1 - tan A tan B), provided the cosine in the bottom is not zero (defined). tan(A-B)=(tan A - tan B)/(1 + tan A tan B). Double: sin 2A = 2 sin A cos A, cos 2A = cos^2 A - sin^2 A = 2 cos^2 A - 1 = 1 - 2 sin^2 A, tan 2A = 2 tan A / (1-tan^2 A). Meaning: divide sin compound by cos compound and divide through by cos A cos B.
- 1. TAN SUM
- Start from sin(A+B)/cos(A+B). Divide num and den by cos A cos B. Bottom 1 - tan A tan B. Undefined when that is 0 (A+B odd multiple of 90 degrees school).
- 2. DOUBLE
- Put B=A. Three forms of cos 2A are all useful (pick the one that matches sin or cos on the paper). Half-angle later if asked via rearranging cos 2A.
Relationship
- tan(A+B)=s+t1-st
- sin 2A = 2 sin A cos A
Overview
Divide sin/cos, then double:
Tan Sum
Start from sin(A+B)/cos(A+B). Divide num and den by cos A cos B. Bottom 1 - tan A tan B. Undefined when that is 0 (A+B odd multiple of 90 degrees school).
Examples 1 - product in bottom · Defined when cos(A+B)!=0 · tan(A-B) plus in bottom
Double
Put B=A. Three forms of cos 2A are all useful (pick the one that matches sin or cos on the paper). Half-angle later if asked via rearranging cos 2A.
Examples 2 sin cos · cos^2-sin^2 · 2t/(1-t^2) for tan
WHAT — TAN(A±B) AND DOUBLE ANGLE
tan(A+B)=tan A + tan B1 - tan A tan B, provided the cosine in the bottom is not zero (defined). tan(A-B)=tan A - tan B1 + tan A tan B. Double: sin 2A = 2 sin A cos A, cos 2A = cos2 A - sin2 A = 2 cos2 A - 1 = 1 - 2 sin2 A, tan 2A = 2 tan A1-tan2 A. Meaning: divide sin compound by cos compound and divide through by cos A cos B.
RULE — 1. TAN SUM
Start from sin(A+B)/cos(A+B). Divide num and den by cos A cos B. Bottom 1 - tan A tan B. Undefined when that is 0 (A+B odd multiple of 90 degrees school).
METHOD — 2. DOUBLE
Put B=A. Three forms of cos 2A are all useful (pick the one that matches sin or cos on the paper). Half-angle later if asked via rearranging cos 2A.
WORKED EXAMPLE
Worked: tan 75 = tan(45+30). tan45=1, tan30=1/sqrt(3) tan75 = 1 + 1/sqrt(3)1 - 1/sqrt(3) times sqrt(3)/sqrt(3): sqrt(3)+1sqrt(3)-1
How to answer a tan(a±b) and double angle question
- Identify the given quantities, notation, and required result.
- Choose the matching rule and write it before substitution.
- Work one algebraic step at a time, keeping brackets and signs clear.
- Check restrictions, simplify the result, and verify it where possible.
Worked example
- tan 75 = tan(45+30).
- tan45=1, tan30=1/sqrt(3)
- tan75 = 1 + 1/sqrt(3)1 - 1/sqrt(3)
- times sqrt(3)/sqrt(3): sqrt(3)+1sqrt(3)-1
In simple words
Bottom 1 - tan A tan B. If you write 1 + by accident, A+B is wrong.
Key points
- tan(A+B)=s+t1-st
- sin 2A = 2 sin A cos A
- divide by cos cos
- B=A
Exam preparation
Exam Focus
Quick revision
Revision Zone
Review the key facts, formulas and checks before you move on.Tan(a±b) and Double Angle
Sticky Notes · Quick Revision
Core Idea
- tan(A+B)=tan A + tan B1 - tan A tan B, provided the cosine in the bottom is not zero (defined).
- tan(A-B)=tan A - tan B1 + tan A tan B.
- Double: sin 2A = 2 sin A cos A, cos 2A = cos2 A - sin2 A = 2 cos2 A - 1 = 1 - 2 sin2 A, tan 2A = 2 tan A1-tan2 A.
1. TAN SUM
- Start from sin(A+B)/cos(A+B).
- Divide num and den by cos A cos B.
- Bottom 1 - tan A tan B.
- Undefined when that is 0 (A+B odd multiple of 90 degrees school).
2. DOUBLE
- Put B=A.
- Three forms of cos 2A are all useful (pick the one that matches sin or cos on the paper).
- Half-angle later if asked via rearranging cos 2A.
Worked Example
- Worked: tan 75 = tan(45+30).
- tan45=1, tan30=1/sqrt(3)
- tan75 = 1 + 1/sqrt(3)1 - 1/sqrt(3)
- times sqrt(3)/sqrt(3): sqrt(3)+1sqrt(3)-1
Common Misconception
- Bottom 1 - tan A tan B. If you write 1 + by accident, A+B is wrong.
FBISE Exam Check
- State the rule for tan(a±b) and double angle before substituting values.
- Show the main algebra steps, keep exact values where possible, and check every condition.
60-second revision
- tan(A+B)=tan A + tan B1 - tan A tan B, provided the cosine in the bottom is not zero (defined).
- tan(A-B)=tan A - tan B1 + tan A tan B.
- Double: sin 2A = 2 sin A cos A, cos 2A = cos2 A - sin2 A = 2 cos2 A - 1 = 1 - 2 sin2 A, tan 2A = 2 tan A1-tan2 A.
- Bottom 1 - tan A tan B. If you write 1 + by accident, A+B is wrong.
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