PhysicsChapter 3: Translatory Motion

Maximum Range

27. Maximum Range

For a fixed initial speed: R = vi² sin 2θ / g The maximum value of sine is: sin 2θ = 1 Therefore: 2θ = 90° θ = 45° Maximum range is: Rmax = vi²g

Your answer is saved with your learning record. It does not mark the topic as mastered.

Quick revision

Review the key facts, formulas and checks before you move on.

Sticky Notes · Quick Revision

You've completed the learning section.

Same supplied content as this Notes page (shared canonical source).