PhysicsChapter 3: Translatory Motion

Maximum Height

23. Maximum Height

At maximum height: vy = 0 Using: vy² = viy² − 2gH Substituting: 0 = (vi sin θ)² − 2gH 2gH = vi² sin² θ Therefore: H = vi² sin² θ2g Only the vertical component determines maximum height.

30. Motion at the Highest Point

At maximum height: vy = 0 However, horizontal velocity remains: vx = vi cos θ Therefore, the projectile’s total velocity is not zero: v = vi cos θ Acceleration also remains: a_y = −g So, at maximum height: Vertical velocity is zero. Horizontal velocity is non-zero. Acceleration is vertically downward.

Did you understand this topic?

Your answer is saved with your learning record. It does not mark the topic as mastered.

Quick revision

Revision Zone

Review the key facts, formulas and checks before you move on.

Maximum Height

Sticky Notes · Quick Revision

At maximum height

At maximum height, v_y = 0.
Horizontal velocity stays non-zero.
Acceleration remains −g (upward positive).

Ready to test yourself?

You've completed the learning section.

1 concept questions
Easy → Medium → Hard
Explanation after each answer

Practice

Practice
Q1. What happens to v_y at maximum height?
Practice
Q2. A projectile is launched at 20 m s⁻¹ and 30°. Find its maximum height.

Exam Practice

Important Short Question
Q1. Is velocity zero at maximum height?

Ask Tutor about this Open in Topics

Same supplied content as this Notes page (shared canonical source).

PhysicsChapter 3: Translatory Motion

Maximum Height

23. Maximum Height

At maximum height: vy = 0 Using: vy² = viy² − 2gH Substituting: 0 = (vi sin θ)² − 2gH 2gH = vi² sin² θ Therefore: H = vi² sin² θ2g Only the vertical component determines maximum height.

30. Motion at the Highest Point

Did you understand this topic?

Your answer is saved with your learning record. It does not mark the topic as mastered.

Quick revision

Revision Zone

Review the key facts, formulas and checks before you move on.

Maximum Height

Sticky Notes · Quick Revision

At maximum height

At maximum height, v_y = 0.
Horizontal velocity stays non-zero.
Acceleration remains −g (upward positive).

Ready to test yourself?

You've completed the learning section.

1 concept questions
Easy → Medium → Hard
Explanation after each answer

Practice

Practice
Q1. What happens to v_y at maximum height?
Practice
Q2. A projectile is launched at 20 m s⁻¹ and 30°. Find its maximum height.

Exam Practice

Important Short Question
Q1. Is velocity zero at maximum height?

Ask Tutor about this Open in Topics

Same supplied content as this Notes page (shared canonical source).