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Maximum Height
At maximum height, vy = 0. Maximum height is H = vi² sin² θ2g. Horizontal velocity remains non-zero.
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23. Maximum Height
At maximum height: vy = 0 Using: vy² = viy² − 2gH Substituting: 0 = (vi sin θ)² − 2gH 2gH = vi² sin² θ Therefore: H = vi² sin² θ2g Only the vertical component determines maximum height.
30. Motion at the Highest Point
At maximum height: vy = 0 However, horizontal velocity remains: vx = vi cos θ Therefore, the projectile’s total velocity is not zero: v = vi cos θ Acceleration also remains: a_y = −g So, at maximum height: Vertical velocity is zero. Horizontal velocity is non-zero. Acceleration is vertically downward.
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Practice
Practice
Q1. What happens to v_y at maximum height?
Practice
Q2. A projectile is launched at 20 m s⁻¹ and 30°. Find its maximum height.
Exam Practice
Important Short Question
Q1. Is velocity zero at maximum height?