1 min read
Time of Flight
For equal launch and landing heights, T = 2 vi sin θg = 2 ts.
Mastery0%
Progress0/5 activities
Did you understand this topic?
Your answer is saved with your learning record. It does not mark the topic as mastered.
Choose Your Level
Recommended for Class 11
25. Time of Flight
When the projectile returns to the same vertical level: y = 0 Using: y = vi sin θ · T − ½g T² 0 = vi sin θ · T − ½g T² Factoring T: T (vi sin θ − ½g T) = 0 Ignoring the initial value T = 0: vi sin θ = ½g T Therefore: T = 2 vi sin θg Also: T = 2 ts This equation is valid when projection and landing points are at the same height.
Practice
Practice
Q1. Calculate the time of flight for the projectile in Question 2.